S\u1ed1 \u0111\u00e1 l\u00e0 g\u00ec? C\u00f3 g\u00ec kh\u00e1c v\u1edbi c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean hay kh\u00f4ng? C\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 v\u00e0 \u0111\u00e1nh \u0111\u1ec1 s\u1ed1 \u0111\u00e1 anh em c\u1ea7n bi\u1ebft \u0111\u1ec3 tr\u00e1nh b\u1ecb l\u1ed7.<\/p>\n
S\u1ed1 \u0111\u00e1 l\u00e0 g\u00ec?<\/span><\/h2>\n\u0110\u00e1nh s\u1ed1 \u0111\u00e1 l\u00e0 m\u1ed9t c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u01b0\u1eddi mi\u1ec1n Nam. Nhi\u1ec1u ng\u01b0\u1eddi s\u1ebd l\u1ea7m t\u01b0\u1edfng c\u00e1ch \u0111\u00e1nh n\u00e0y v\u1edbi l\u00f4 xi\u00ean v\u00e0 bao l\u00f4 b\u00ecnh th\u01b0\u1eddng. Tuy nhi\u00ean c\u00f3 m\u1ed9t v\u00e0i \u0111i\u1ec3m kh\u00e1c bi\u1ec7t m\u00e0 trong b\u00e0i vi\u1ebft l\u1ea7n n\u00e0y V\u0169 s\u1ebd gi\u1ea3i th\u00edch c\u1eb7n k\u1ebd cho anh em c\u00f9ng n\u1eafm r\u00f5.<\/p>\n
C\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1<\/span><\/h2>\nS\u1ef1 kh\u00e1c nhau gi\u1eefa c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 v\u00e0 l\u00f4 xi\u00ean<\/span><\/h3>\nNh\u01b0 V\u0169 \u0111\u00e3 t\u1eebng gi\u1ea3i th\u00edch \u1edf tr\u00ean, s\u1ed1 \u0111\u00e1 kh\u00f4ng ph\u1ea3i l\u00e0 l\u00f4 xi\u00ean hay l\u00f4 xi\u00ean quay m\u00e0 nhi\u1ec1u ng\u01b0\u1eddi v\u1eabn th\u01b0\u1eddng t\u01b0\u1edfng. N\u00f3 l\u00e0 m\u1ed9t c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 kh\u00e1 c\u00f3 l\u1ee3i \u0111\u1ed1i v\u1edbi ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1 b\u1eaft ngu\u1ed3n t\u1eeb mi\u1ec1n Nam.<\/p>\n
S\u1ed1 \u0111\u00e1 c\u00f3 \u0111i\u1ec3m gi\u1ed1ng v\u1edbi l\u00f4 xi\u00ean \u1edf ch\u1ed7 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn nhi\u1ec1u b\u1ed9 s\u1ed1 c\u00f9ng ch\u01a1i m\u1ed9t l\u00fac. M\u1ed9t \u0111i\u1ec3m gi\u1ed1ng v\u1edbi l\u00f4 xi\u00ean n\u1eefa \u0111\u00f3 ch\u00ednh l\u00e0 ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn l\u1ecdc \u0111\u00e1 bao nhi\u00eau l\u00f4 t\u00f9y th\u00edch. Tuy nhi\u00ean, kh\u00f4ng nh\u1ea5t thi\u1ebft to\u00e0n b\u1ed9 nh\u1eefng con l\u00f4 ph\u1ea3i ra th\u00ec m\u1edbi tr\u00fang \u0111\u01b0\u1ee3c gi\u1ed1ng nh\u01b0 c\u00e1ch ch\u01a1i \u0111\u00f3.<\/p>\n
T\u00f3m l\u1ea1i<\/span><\/h4>\nKh\u00f4ng gi\u1ed1ng l\u00f4 xi\u00ean ph\u1ea3i ra h\u1ebft t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 trong xi\u00ean th\u00ec m\u1edbi th\u1eafng. \u0110\u1ed1i v\u1edbi s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u1ea7n c\u00f3 m\u1ed9t c\u1eb7p s\u1ed1 ra trong k\u1ebft qu\u1ea3 m\u1edf th\u01b0\u1edfng th\u00ec coi nh\u01b0 ng\u01b0\u1eddi ch\u01a1i \u0111\u00e3 tr\u00fang s\u1ed1. C\u00f2n v\u1ec1 ph\u1ea7n ti\u1ec1n tr\u1ea3 th\u01b0\u1edfng s\u1ebd theo t\u1ef7 l\u1ec7 t\u00f9y thu\u1ed9c v\u00e0o s\u1ed1 l\u00f4 ch\u1ecdn \u0111\u00e1nh s\u1ed1 \u0111\u00e1.
\nAnh em n\u00e0o mu\u1ed1n \u0111\u1ecdc th\u00eam v\u1ec1 l\u00f4 xi\u00ean ho\u1eb7c c\u00f3 \u0111i\u1ec1u g\u00ec ch\u01b0a r\u00f5 v\u1ec1 l\u00f4 xi\u00ean th\u00ec click ngay v\u00e0o \u0111\u00e2y nh\u00e9.<\/p>\n
S\u1ed1 \u0111\u00e1 \u0103n bao nhi\u00eau?<\/span><\/h2>\nNh\u01b0 \u0111\u00e3 \u0111\u1ec1 c\u1eadp, ti\u1ec1n c\u01b0\u1ee3c c\u1ee7a s\u1ed1 \u0111\u00e1 s\u1ebd c\u00f3 thay \u0111\u1ed5i t\u00f9y theo s\u1ed1 con l\u00f4 anh em ch\u1ecdn ch\u01a1i v\u00e0 s\u1ed1 l\u00f4 ra trong k\u1ebft qu\u1ea3 m\u1edf th\u01b0\u1edfng. Ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u00e1 th\u01b0\u1eddng s\u1ebd l\u1ef1a ch\u1ecdn \u0111\u00e1nh t\u1eeb 2 cho t\u1edbi 5 con l\u00f4. Ti\u1ec1n x\u00e1c khi ch\u1ecdn ch\u01a1i l\u00f4 \u0111\u00e1 l\u00e0 1 \u0111i\u1ec3m = 48k. T\u1eeb \u0111\u00f3 ch\u00fang ta c\u00f3:<\/p>\n
\n- \u0110\u00e1 l\u00f4 2 c\u1eb7p c\u00f3 ti\u1ec1n c\u01b0\u1ee3c l\u00e0 48k<\/li>\n
- \u0110\u00e1 l\u00f4 3 c\u1eb7p ti\u1ec1n c\u01b0\u1ee3c nh\u00e2n 3, t\u1ee9c 48*3=144k<\/li>\n
- \u0110\u00e1 l\u00f4 4 c\u1eb7p s\u1ebd c\u00f3 ti\u1ec1n x\u00e1c nh\u00e2n 6, t\u1ee9c (48*6=) 288k<\/li>\n
- T\u01b0\u01a1ng t\u1ef1 \u0111\u00e1 l\u00f4 5 con m\u1ea5t s\u1ed1 ti\u1ec1n x\u00e1c nh\u00e2n 10 l\u00e0 480k<\/li>\n<\/ul>\n
T\u1ef7 l\u1ec7 \u0103n s\u1ed1 \u0111\u00e1 l\u00e0 1 : 12,5. M\u1ed9t tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t n\u1ebfu ch\u01a1i \u0111\u00e1 l\u00f4 2 c\u1eb7p th\u00ec ti\u1ec1n \u0103n s\u1ebd g\u1ea5p 25 l\u1ea7n ti\u1ec1n x\u00e1c (1:25)<\/p>\n
S\u1ed1 \u0111\u00e1 v\u1ed1n r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i x\u1ed5 s\u1ed1 l\u00f4 \u0111\u1ec1 mi\u1ec1n Nam. V\u00e0 trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 th\u00ec ti\u1ec1n l\u1eddi l\u00e3i khi \u0111\u00e1nh s\u1ed1 \u0111\u00e1 2, 3, 4, 5 s\u1ebd c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
\u0110\u00e1 l\u00f4 2 c\u00f3 ti\u1ec1n l\u00e3i c\u1ee5 th\u1ec3 nh\u01b0 th\u1ebf n\u00e0o?<\/span><\/h3>\n\u0110\u00e1 l\u00f4 2 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ch\u01a1i 1 c\u1eb7p l\u00f4 (1 v\u00f2ng d\u1ef1 th\u01b0\u1edfng theo c\u00e1ch n\u00f3i c\u1ee7a nhi\u1ec1u ch\u1ed7 kh\u00e1c).<\/p>\n
VD: \u0110\u00e1 l\u00f4 2 s\u1ed1 12-23 (1 v\u00f2ng)<\/p>\n
Khi ch\u01a1i \u0111\u00e1 l\u00f4 2, KQXS v\u1ec1 c\u1ea3 2 con l\u00f4 (kh\u00f4ng v\u1ec1 nhi\u1ec1u nh\u00e1y) th\u00ec anh em c\u00f3 ti\u1ec1n tr\u00fang 48*12.5=600k.<\/p>\n
Ti\u1ec1n l\u00e3i s\u1ed1 \u0111\u00e1 3 trong v\u00e0i tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3<\/span><\/h3>\n\u0110\u00e1 l\u00f4 3 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ra 3 con s\u1ed1, 3 con s\u1ed1 n\u00e0y s\u1ebd t\u1ea1o th\u00e0nh 3 c\u1eb7p s\u1ed1 (3 v\u00f2ng d\u1ef1 th\u01b0\u1edfng).<\/p>\n
VD: S\u1ed1 \u0111\u00e1 3 con l\u00f4 12 23 34 t\u1ea1o th\u00e0nh 3 c\u1eb7p 12-23; 23-34; 34-12 (3 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 3 con, n\u1ebfu v\u1ec1 2 con s\u1ed1 (v\u1ec1 1 c\u1eb7p l\u00f4) th\u00ec m\u1edbi xem l\u00e0 tr\u00fang s\u1ed1 \u0111\u00e1. C\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00fang \u0111\u01b0\u1ee3c chia c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 2 tr\u00ean t\u1ed5ng 3 s\u1ed1 (tr\u00fang 1 c\u1eb7p): ti\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang 2 s\u1ed1 v\u00e0 c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y. VD: \u0111\u00e1nh 11 22 33 v\u00e0 v\u1ec1 11; 22 v\u1ec1 2 nh\u00e1y, 33 c\u00e2m.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam n\u1eeda v\u00f2ng, t\u1ee9c l\u00e0 ti\u1ec1n x\u00e1c 1 c\u1eb7p l\u00f4 nh\u00e2n t\u1ef7 l\u1ec7 \u0103n c\u01b0a \u0111\u00f4i.
\n48 * 12.5 \/ 2 = 300k<\/li>\n - Tr\u00fang 2 s\u1ed1, trong \u0111\u00f3 c\u00f3 1 s\u1ed1 v\u1ec1 3 nh\u00e1y. VD: v\u1ec1 11 v\u00e0 22 v\u1ec1 3 nh\u00e1y, 33 kh\u00f4ng v\u1ec1.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam 1 v\u00f2ng.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang c\u1ea3 3 s\u1ed1 (t\u1ee9c v\u1ec1 c\u1ea3 3 c\u1eb7p) th\u00ec t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7 nh\u01b0 th\u01b0\u1eddng.
\n144 * 12.5 = 1800k<\/li>\n<\/ul>\n<\/div>\nC\u00e1ch ch\u01a1i S\u1ed1 \u0111\u00e1 4 c\u00f3 ti\u1ec1n l\u1eddi th\u1ebf n\u00e0o?<\/span><\/h3>\nT\u01b0\u1eddng t\u1ef1 ch\u00fang ta c\u00f3 ti\u1ebfp \u0111\u00e1 l\u00f4 4 l\u00e0 ch\u1ecdn ra 4 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 6 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (6 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 4 con, ch\u00fang s\u1ebd t\u1ea1o th\u00e0nh 6 c\u1eb7p, ch\u1ec9 c\u1ea7n c\u00f3 1 c\u1eb7p (t\u1ee9c l\u00e0 2 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1) v\u1ec1 th\u00ec anh em tr\u00fang s\u1ed1. Chia ra c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 1 c\u1eb7p: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.<\/li>\n
- V\u1ec1 3 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 3<\/li>\n
- V\u1ec1 c\u1ea3 4 s\u1ed1: t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7: 288 * 12.5 = 3600k<\/li>\n
- Trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00ean, n\u1ebfu c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y th\u00ec t\u00ednh ti\u1ec1n l\u00e3i th\u00eam n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 \u0111i\u1ec3m nh\u00e2n v\u1edbi t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/li>\n<\/ul>\n
Ti\u1ec1n l\u1eddi s\u1ed1 \u0111\u00e1 5 trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p<\/span><\/h3>\nS\u1ed1 \u0111\u00e1 5: ch\u1ecdn ra 5 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 10 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (10 v\u00f2ng)<\/p>\n
\u0110\u00e1nh s\u1ed1 \u0111\u00e1 5 c\u00f3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0103n ti\u1ec1n l\u00e3i t\u1eeb 2 cho t\u1edbi 4 s\u1ed1 tr\u00ean t\u1ed5ng 5 s\u1ed1 gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0111\u00e3 k\u1ec3 tr\u00ean.<\/p>\n
N\u1ebfu ra c\u1ea3 5 con s\u1ed1 th\u00ec ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c 10 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7, s\u1ebd l\u00e0 12.5 * 480 = 6000k. Gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p s\u1ed1 \u0111\u00e1 3 v\u00e0 4, n\u1ebfu c\u00f3 s\u1ed1 v\u1ec1 nhi\u1ec1u th\u00eam 1 nh\u00e1y th\u00ec t\u00ednh l\u00e0 \u0103n n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/p>\n
K\u1ebft lu\u1eadn<\/span><\/h2>\nNh\u00ecn chung, c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 n\u00e0y r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. Kh\u00e1 gi\u1ed1ng v\u1edbi \u0111\u00e1nh nhi\u1ec1u c\u00e1i l\u00f4 xi\u00ean 2, 3, 4 m\u1ed9t l\u00fac nh\u01b0ng ti\u1ec1n x\u00e1c v\u00e0 t\u1ef7 l\u1ec7 \u0103n th\u00ec c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
Anh em ch\u01a1i s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u00f3 th\u1ec3 ch\u01a1i \u1edf mi\u1ec1n Nam. \u1ede mi\u1ec1n B\u1eafc kh\u00f4ng th\u1ea5y ph\u1ed5 bi\u1ebfn c\u00e1ch ch\u01a1i n\u00e0y. Ch\u01a1i \u0111\u00e0i mi\u1ec1n Nam r\u1ea5t kh\u00f3 v\u00ec c\u00f3 qu\u00e1 nhi\u1ec1u \u0111\u00e0i v\u00e0 kh\u00f3 soi c\u1ea7u b\u1eaft s\u1ed1. Tuy nhi\u00ean v\u1edbi c\u00e1ch \u0111\u00e1nh n\u00e0y, hy v\u1ecdng ch\u00fang t\u00f4i \u0111\u00e3 cho anh em th\u1ea5y \u0111\u01b0\u1ee3c m\u1ed9t l\u1ed1i ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1edbi cho m\u00ecnh. B\u1ea3n th\u00e2n V\u0169 th\u1ea5y c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 th\u1eadt s\u1ef1 h\u1eefu d\u1ee5ng. Do \u0111\u00f3 c\u0169ng mong anh em c\u00e2n nh\u1eafc ch\u01a1i c\u00e1ch n\u00e0y nhi\u1ec1u h\u01a1n.<\/p>\n<\/div>\n<\/div>\n<\/article>\n
<\/main><\/div>\n
S\u1ef1 kh\u00e1c nhau gi\u1eefa c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 v\u00e0 l\u00f4 xi\u00ean<\/span><\/h3>\nNh\u01b0 V\u0169 \u0111\u00e3 t\u1eebng gi\u1ea3i th\u00edch \u1edf tr\u00ean, s\u1ed1 \u0111\u00e1 kh\u00f4ng ph\u1ea3i l\u00e0 l\u00f4 xi\u00ean hay l\u00f4 xi\u00ean quay m\u00e0 nhi\u1ec1u ng\u01b0\u1eddi v\u1eabn th\u01b0\u1eddng t\u01b0\u1edfng. N\u00f3 l\u00e0 m\u1ed9t c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 kh\u00e1 c\u00f3 l\u1ee3i \u0111\u1ed1i v\u1edbi ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1 b\u1eaft ngu\u1ed3n t\u1eeb mi\u1ec1n Nam.<\/p>\n
S\u1ed1 \u0111\u00e1 c\u00f3 \u0111i\u1ec3m gi\u1ed1ng v\u1edbi l\u00f4 xi\u00ean \u1edf ch\u1ed7 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn nhi\u1ec1u b\u1ed9 s\u1ed1 c\u00f9ng ch\u01a1i m\u1ed9t l\u00fac. M\u1ed9t \u0111i\u1ec3m gi\u1ed1ng v\u1edbi l\u00f4 xi\u00ean n\u1eefa \u0111\u00f3 ch\u00ednh l\u00e0 ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn l\u1ecdc \u0111\u00e1 bao nhi\u00eau l\u00f4 t\u00f9y th\u00edch. Tuy nhi\u00ean, kh\u00f4ng nh\u1ea5t thi\u1ebft to\u00e0n b\u1ed9 nh\u1eefng con l\u00f4 ph\u1ea3i ra th\u00ec m\u1edbi tr\u00fang \u0111\u01b0\u1ee3c gi\u1ed1ng nh\u01b0 c\u00e1ch ch\u01a1i \u0111\u00f3.<\/p>\n
T\u00f3m l\u1ea1i<\/span><\/h4>\nKh\u00f4ng gi\u1ed1ng l\u00f4 xi\u00ean ph\u1ea3i ra h\u1ebft t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 trong xi\u00ean th\u00ec m\u1edbi th\u1eafng. \u0110\u1ed1i v\u1edbi s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u1ea7n c\u00f3 m\u1ed9t c\u1eb7p s\u1ed1 ra trong k\u1ebft qu\u1ea3 m\u1edf th\u01b0\u1edfng th\u00ec coi nh\u01b0 ng\u01b0\u1eddi ch\u01a1i \u0111\u00e3 tr\u00fang s\u1ed1. C\u00f2n v\u1ec1 ph\u1ea7n ti\u1ec1n tr\u1ea3 th\u01b0\u1edfng s\u1ebd theo t\u1ef7 l\u1ec7 t\u00f9y thu\u1ed9c v\u00e0o s\u1ed1 l\u00f4 ch\u1ecdn \u0111\u00e1nh s\u1ed1 \u0111\u00e1.
\nAnh em n\u00e0o mu\u1ed1n \u0111\u1ecdc th\u00eam v\u1ec1 l\u00f4 xi\u00ean ho\u1eb7c c\u00f3 \u0111i\u1ec1u g\u00ec ch\u01b0a r\u00f5 v\u1ec1 l\u00f4 xi\u00ean th\u00ec click ngay v\u00e0o \u0111\u00e2y nh\u00e9.<\/p>\n
S\u1ed1 \u0111\u00e1 \u0103n bao nhi\u00eau?<\/span><\/h2>\nNh\u01b0 \u0111\u00e3 \u0111\u1ec1 c\u1eadp, ti\u1ec1n c\u01b0\u1ee3c c\u1ee7a s\u1ed1 \u0111\u00e1 s\u1ebd c\u00f3 thay \u0111\u1ed5i t\u00f9y theo s\u1ed1 con l\u00f4 anh em ch\u1ecdn ch\u01a1i v\u00e0 s\u1ed1 l\u00f4 ra trong k\u1ebft qu\u1ea3 m\u1edf th\u01b0\u1edfng. Ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u00e1 th\u01b0\u1eddng s\u1ebd l\u1ef1a ch\u1ecdn \u0111\u00e1nh t\u1eeb 2 cho t\u1edbi 5 con l\u00f4. Ti\u1ec1n x\u00e1c khi ch\u1ecdn ch\u01a1i l\u00f4 \u0111\u00e1 l\u00e0 1 \u0111i\u1ec3m = 48k. T\u1eeb \u0111\u00f3 ch\u00fang ta c\u00f3:<\/p>\n
\n- \u0110\u00e1 l\u00f4 2 c\u1eb7p c\u00f3 ti\u1ec1n c\u01b0\u1ee3c l\u00e0 48k<\/li>\n
- \u0110\u00e1 l\u00f4 3 c\u1eb7p ti\u1ec1n c\u01b0\u1ee3c nh\u00e2n 3, t\u1ee9c 48*3=144k<\/li>\n
- \u0110\u00e1 l\u00f4 4 c\u1eb7p s\u1ebd c\u00f3 ti\u1ec1n x\u00e1c nh\u00e2n 6, t\u1ee9c (48*6=) 288k<\/li>\n
- T\u01b0\u01a1ng t\u1ef1 \u0111\u00e1 l\u00f4 5 con m\u1ea5t s\u1ed1 ti\u1ec1n x\u00e1c nh\u00e2n 10 l\u00e0 480k<\/li>\n<\/ul>\n
T\u1ef7 l\u1ec7 \u0103n s\u1ed1 \u0111\u00e1 l\u00e0 1 : 12,5. M\u1ed9t tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t n\u1ebfu ch\u01a1i \u0111\u00e1 l\u00f4 2 c\u1eb7p th\u00ec ti\u1ec1n \u0103n s\u1ebd g\u1ea5p 25 l\u1ea7n ti\u1ec1n x\u00e1c (1:25)<\/p>\n
S\u1ed1 \u0111\u00e1 v\u1ed1n r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i x\u1ed5 s\u1ed1 l\u00f4 \u0111\u1ec1 mi\u1ec1n Nam. V\u00e0 trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 th\u00ec ti\u1ec1n l\u1eddi l\u00e3i khi \u0111\u00e1nh s\u1ed1 \u0111\u00e1 2, 3, 4, 5 s\u1ebd c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
\u0110\u00e1 l\u00f4 2 c\u00f3 ti\u1ec1n l\u00e3i c\u1ee5 th\u1ec3 nh\u01b0 th\u1ebf n\u00e0o?<\/span><\/h3>\n\u0110\u00e1 l\u00f4 2 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ch\u01a1i 1 c\u1eb7p l\u00f4 (1 v\u00f2ng d\u1ef1 th\u01b0\u1edfng theo c\u00e1ch n\u00f3i c\u1ee7a nhi\u1ec1u ch\u1ed7 kh\u00e1c).<\/p>\n
VD: \u0110\u00e1 l\u00f4 2 s\u1ed1 12-23 (1 v\u00f2ng)<\/p>\n
Khi ch\u01a1i \u0111\u00e1 l\u00f4 2, KQXS v\u1ec1 c\u1ea3 2 con l\u00f4 (kh\u00f4ng v\u1ec1 nhi\u1ec1u nh\u00e1y) th\u00ec anh em c\u00f3 ti\u1ec1n tr\u00fang 48*12.5=600k.<\/p>\n
Ti\u1ec1n l\u00e3i s\u1ed1 \u0111\u00e1 3 trong v\u00e0i tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3<\/span><\/h3>\n\u0110\u00e1 l\u00f4 3 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ra 3 con s\u1ed1, 3 con s\u1ed1 n\u00e0y s\u1ebd t\u1ea1o th\u00e0nh 3 c\u1eb7p s\u1ed1 (3 v\u00f2ng d\u1ef1 th\u01b0\u1edfng).<\/p>\n
VD: S\u1ed1 \u0111\u00e1 3 con l\u00f4 12 23 34 t\u1ea1o th\u00e0nh 3 c\u1eb7p 12-23; 23-34; 34-12 (3 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 3 con, n\u1ebfu v\u1ec1 2 con s\u1ed1 (v\u1ec1 1 c\u1eb7p l\u00f4) th\u00ec m\u1edbi xem l\u00e0 tr\u00fang s\u1ed1 \u0111\u00e1. C\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00fang \u0111\u01b0\u1ee3c chia c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 2 tr\u00ean t\u1ed5ng 3 s\u1ed1 (tr\u00fang 1 c\u1eb7p): ti\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang 2 s\u1ed1 v\u00e0 c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y. VD: \u0111\u00e1nh 11 22 33 v\u00e0 v\u1ec1 11; 22 v\u1ec1 2 nh\u00e1y, 33 c\u00e2m.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam n\u1eeda v\u00f2ng, t\u1ee9c l\u00e0 ti\u1ec1n x\u00e1c 1 c\u1eb7p l\u00f4 nh\u00e2n t\u1ef7 l\u1ec7 \u0103n c\u01b0a \u0111\u00f4i.
\n48 * 12.5 \/ 2 = 300k<\/li>\n - Tr\u00fang 2 s\u1ed1, trong \u0111\u00f3 c\u00f3 1 s\u1ed1 v\u1ec1 3 nh\u00e1y. VD: v\u1ec1 11 v\u00e0 22 v\u1ec1 3 nh\u00e1y, 33 kh\u00f4ng v\u1ec1.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam 1 v\u00f2ng.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang c\u1ea3 3 s\u1ed1 (t\u1ee9c v\u1ec1 c\u1ea3 3 c\u1eb7p) th\u00ec t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7 nh\u01b0 th\u01b0\u1eddng.
\n144 * 12.5 = 1800k<\/li>\n<\/ul>\n<\/div>\nC\u00e1ch ch\u01a1i S\u1ed1 \u0111\u00e1 4 c\u00f3 ti\u1ec1n l\u1eddi th\u1ebf n\u00e0o?<\/span><\/h3>\nT\u01b0\u1eddng t\u1ef1 ch\u00fang ta c\u00f3 ti\u1ebfp \u0111\u00e1 l\u00f4 4 l\u00e0 ch\u1ecdn ra 4 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 6 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (6 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 4 con, ch\u00fang s\u1ebd t\u1ea1o th\u00e0nh 6 c\u1eb7p, ch\u1ec9 c\u1ea7n c\u00f3 1 c\u1eb7p (t\u1ee9c l\u00e0 2 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1) v\u1ec1 th\u00ec anh em tr\u00fang s\u1ed1. Chia ra c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 1 c\u1eb7p: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.<\/li>\n
- V\u1ec1 3 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 3<\/li>\n
- V\u1ec1 c\u1ea3 4 s\u1ed1: t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7: 288 * 12.5 = 3600k<\/li>\n
- Trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00ean, n\u1ebfu c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y th\u00ec t\u00ednh ti\u1ec1n l\u00e3i th\u00eam n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 \u0111i\u1ec3m nh\u00e2n v\u1edbi t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/li>\n<\/ul>\n
Ti\u1ec1n l\u1eddi s\u1ed1 \u0111\u00e1 5 trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p<\/span><\/h3>\nS\u1ed1 \u0111\u00e1 5: ch\u1ecdn ra 5 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 10 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (10 v\u00f2ng)<\/p>\n
\u0110\u00e1nh s\u1ed1 \u0111\u00e1 5 c\u00f3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0103n ti\u1ec1n l\u00e3i t\u1eeb 2 cho t\u1edbi 4 s\u1ed1 tr\u00ean t\u1ed5ng 5 s\u1ed1 gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0111\u00e3 k\u1ec3 tr\u00ean.<\/p>\n
N\u1ebfu ra c\u1ea3 5 con s\u1ed1 th\u00ec ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c 10 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7, s\u1ebd l\u00e0 12.5 * 480 = 6000k. Gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p s\u1ed1 \u0111\u00e1 3 v\u00e0 4, n\u1ebfu c\u00f3 s\u1ed1 v\u1ec1 nhi\u1ec1u th\u00eam 1 nh\u00e1y th\u00ec t\u00ednh l\u00e0 \u0103n n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/p>\n
K\u1ebft lu\u1eadn<\/span><\/h2>\nNh\u00ecn chung, c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 n\u00e0y r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. Kh\u00e1 gi\u1ed1ng v\u1edbi \u0111\u00e1nh nhi\u1ec1u c\u00e1i l\u00f4 xi\u00ean 2, 3, 4 m\u1ed9t l\u00fac nh\u01b0ng ti\u1ec1n x\u00e1c v\u00e0 t\u1ef7 l\u1ec7 \u0103n th\u00ec c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
Anh em ch\u01a1i s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u00f3 th\u1ec3 ch\u01a1i \u1edf mi\u1ec1n Nam. \u1ede mi\u1ec1n B\u1eafc kh\u00f4ng th\u1ea5y ph\u1ed5 bi\u1ebfn c\u00e1ch ch\u01a1i n\u00e0y. Ch\u01a1i \u0111\u00e0i mi\u1ec1n Nam r\u1ea5t kh\u00f3 v\u00ec c\u00f3 qu\u00e1 nhi\u1ec1u \u0111\u00e0i v\u00e0 kh\u00f3 soi c\u1ea7u b\u1eaft s\u1ed1. Tuy nhi\u00ean v\u1edbi c\u00e1ch \u0111\u00e1nh n\u00e0y, hy v\u1ecdng ch\u00fang t\u00f4i \u0111\u00e3 cho anh em th\u1ea5y \u0111\u01b0\u1ee3c m\u1ed9t l\u1ed1i ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1edbi cho m\u00ecnh. B\u1ea3n th\u00e2n V\u0169 th\u1ea5y c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 th\u1eadt s\u1ef1 h\u1eefu d\u1ee5ng. Do \u0111\u00f3 c\u0169ng mong anh em c\u00e2n nh\u1eafc ch\u01a1i c\u00e1ch n\u00e0y nhi\u1ec1u h\u01a1n.<\/p>\n<\/div>\n<\/div>\n<\/article>\n
<\/main><\/div>\n
Kh\u00f4ng gi\u1ed1ng l\u00f4 xi\u00ean ph\u1ea3i ra h\u1ebft t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 trong xi\u00ean th\u00ec m\u1edbi th\u1eafng. \u0110\u1ed1i v\u1edbi s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u1ea7n c\u00f3 m\u1ed9t c\u1eb7p s\u1ed1 ra trong k\u1ebft qu\u1ea3 m\u1edf th\u01b0\u1edfng th\u00ec coi nh\u01b0 ng\u01b0\u1eddi ch\u01a1i \u0111\u00e3 tr\u00fang s\u1ed1. C\u00f2n v\u1ec1 ph\u1ea7n ti\u1ec1n tr\u1ea3 th\u01b0\u1edfng s\u1ebd theo t\u1ef7 l\u1ec7 t\u00f9y thu\u1ed9c v\u00e0o s\u1ed1 l\u00f4 ch\u1ecdn \u0111\u00e1nh s\u1ed1 \u0111\u00e1.
\nAnh em n\u00e0o mu\u1ed1n \u0111\u1ecdc th\u00eam v\u1ec1 l\u00f4 xi\u00ean ho\u1eb7c c\u00f3 \u0111i\u1ec1u g\u00ec ch\u01b0a r\u00f5 v\u1ec1 l\u00f4 xi\u00ean th\u00ec click ngay v\u00e0o \u0111\u00e2y nh\u00e9.<\/p>\n
S\u1ed1 \u0111\u00e1 \u0103n bao nhi\u00eau?<\/span><\/h2>\nNh\u01b0 \u0111\u00e3 \u0111\u1ec1 c\u1eadp, ti\u1ec1n c\u01b0\u1ee3c c\u1ee7a s\u1ed1 \u0111\u00e1 s\u1ebd c\u00f3 thay \u0111\u1ed5i t\u00f9y theo s\u1ed1 con l\u00f4 anh em ch\u1ecdn ch\u01a1i v\u00e0 s\u1ed1 l\u00f4 ra trong k\u1ebft qu\u1ea3 m\u1edf th\u01b0\u1edfng. Ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u00e1 th\u01b0\u1eddng s\u1ebd l\u1ef1a ch\u1ecdn \u0111\u00e1nh t\u1eeb 2 cho t\u1edbi 5 con l\u00f4. Ti\u1ec1n x\u00e1c khi ch\u1ecdn ch\u01a1i l\u00f4 \u0111\u00e1 l\u00e0 1 \u0111i\u1ec3m = 48k. T\u1eeb \u0111\u00f3 ch\u00fang ta c\u00f3:<\/p>\n
\n- \u0110\u00e1 l\u00f4 2 c\u1eb7p c\u00f3 ti\u1ec1n c\u01b0\u1ee3c l\u00e0 48k<\/li>\n
- \u0110\u00e1 l\u00f4 3 c\u1eb7p ti\u1ec1n c\u01b0\u1ee3c nh\u00e2n 3, t\u1ee9c 48*3=144k<\/li>\n
- \u0110\u00e1 l\u00f4 4 c\u1eb7p s\u1ebd c\u00f3 ti\u1ec1n x\u00e1c nh\u00e2n 6, t\u1ee9c (48*6=) 288k<\/li>\n
- T\u01b0\u01a1ng t\u1ef1 \u0111\u00e1 l\u00f4 5 con m\u1ea5t s\u1ed1 ti\u1ec1n x\u00e1c nh\u00e2n 10 l\u00e0 480k<\/li>\n<\/ul>\n
T\u1ef7 l\u1ec7 \u0103n s\u1ed1 \u0111\u00e1 l\u00e0 1 : 12,5. M\u1ed9t tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t n\u1ebfu ch\u01a1i \u0111\u00e1 l\u00f4 2 c\u1eb7p th\u00ec ti\u1ec1n \u0103n s\u1ebd g\u1ea5p 25 l\u1ea7n ti\u1ec1n x\u00e1c (1:25)<\/p>\n
S\u1ed1 \u0111\u00e1 v\u1ed1n r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i x\u1ed5 s\u1ed1 l\u00f4 \u0111\u1ec1 mi\u1ec1n Nam. V\u00e0 trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 th\u00ec ti\u1ec1n l\u1eddi l\u00e3i khi \u0111\u00e1nh s\u1ed1 \u0111\u00e1 2, 3, 4, 5 s\u1ebd c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
\u0110\u00e1 l\u00f4 2 c\u00f3 ti\u1ec1n l\u00e3i c\u1ee5 th\u1ec3 nh\u01b0 th\u1ebf n\u00e0o?<\/span><\/h3>\n\u0110\u00e1 l\u00f4 2 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ch\u01a1i 1 c\u1eb7p l\u00f4 (1 v\u00f2ng d\u1ef1 th\u01b0\u1edfng theo c\u00e1ch n\u00f3i c\u1ee7a nhi\u1ec1u ch\u1ed7 kh\u00e1c).<\/p>\n
VD: \u0110\u00e1 l\u00f4 2 s\u1ed1 12-23 (1 v\u00f2ng)<\/p>\n
Khi ch\u01a1i \u0111\u00e1 l\u00f4 2, KQXS v\u1ec1 c\u1ea3 2 con l\u00f4 (kh\u00f4ng v\u1ec1 nhi\u1ec1u nh\u00e1y) th\u00ec anh em c\u00f3 ti\u1ec1n tr\u00fang 48*12.5=600k.<\/p>\n
Ti\u1ec1n l\u00e3i s\u1ed1 \u0111\u00e1 3 trong v\u00e0i tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3<\/span><\/h3>\n\u0110\u00e1 l\u00f4 3 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ra 3 con s\u1ed1, 3 con s\u1ed1 n\u00e0y s\u1ebd t\u1ea1o th\u00e0nh 3 c\u1eb7p s\u1ed1 (3 v\u00f2ng d\u1ef1 th\u01b0\u1edfng).<\/p>\n
VD: S\u1ed1 \u0111\u00e1 3 con l\u00f4 12 23 34 t\u1ea1o th\u00e0nh 3 c\u1eb7p 12-23; 23-34; 34-12 (3 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 3 con, n\u1ebfu v\u1ec1 2 con s\u1ed1 (v\u1ec1 1 c\u1eb7p l\u00f4) th\u00ec m\u1edbi xem l\u00e0 tr\u00fang s\u1ed1 \u0111\u00e1. C\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00fang \u0111\u01b0\u1ee3c chia c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 2 tr\u00ean t\u1ed5ng 3 s\u1ed1 (tr\u00fang 1 c\u1eb7p): ti\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang 2 s\u1ed1 v\u00e0 c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y. VD: \u0111\u00e1nh 11 22 33 v\u00e0 v\u1ec1 11; 22 v\u1ec1 2 nh\u00e1y, 33 c\u00e2m.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam n\u1eeda v\u00f2ng, t\u1ee9c l\u00e0 ti\u1ec1n x\u00e1c 1 c\u1eb7p l\u00f4 nh\u00e2n t\u1ef7 l\u1ec7 \u0103n c\u01b0a \u0111\u00f4i.
\n48 * 12.5 \/ 2 = 300k<\/li>\n - Tr\u00fang 2 s\u1ed1, trong \u0111\u00f3 c\u00f3 1 s\u1ed1 v\u1ec1 3 nh\u00e1y. VD: v\u1ec1 11 v\u00e0 22 v\u1ec1 3 nh\u00e1y, 33 kh\u00f4ng v\u1ec1.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam 1 v\u00f2ng.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang c\u1ea3 3 s\u1ed1 (t\u1ee9c v\u1ec1 c\u1ea3 3 c\u1eb7p) th\u00ec t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7 nh\u01b0 th\u01b0\u1eddng.
\n144 * 12.5 = 1800k<\/li>\n<\/ul>\n<\/div>\nC\u00e1ch ch\u01a1i S\u1ed1 \u0111\u00e1 4 c\u00f3 ti\u1ec1n l\u1eddi th\u1ebf n\u00e0o?<\/span><\/h3>\nT\u01b0\u1eddng t\u1ef1 ch\u00fang ta c\u00f3 ti\u1ebfp \u0111\u00e1 l\u00f4 4 l\u00e0 ch\u1ecdn ra 4 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 6 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (6 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 4 con, ch\u00fang s\u1ebd t\u1ea1o th\u00e0nh 6 c\u1eb7p, ch\u1ec9 c\u1ea7n c\u00f3 1 c\u1eb7p (t\u1ee9c l\u00e0 2 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1) v\u1ec1 th\u00ec anh em tr\u00fang s\u1ed1. Chia ra c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 1 c\u1eb7p: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.<\/li>\n
- V\u1ec1 3 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 3<\/li>\n
- V\u1ec1 c\u1ea3 4 s\u1ed1: t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7: 288 * 12.5 = 3600k<\/li>\n
- Trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00ean, n\u1ebfu c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y th\u00ec t\u00ednh ti\u1ec1n l\u00e3i th\u00eam n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 \u0111i\u1ec3m nh\u00e2n v\u1edbi t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/li>\n<\/ul>\n
Ti\u1ec1n l\u1eddi s\u1ed1 \u0111\u00e1 5 trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p<\/span><\/h3>\nS\u1ed1 \u0111\u00e1 5: ch\u1ecdn ra 5 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 10 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (10 v\u00f2ng)<\/p>\n
\u0110\u00e1nh s\u1ed1 \u0111\u00e1 5 c\u00f3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0103n ti\u1ec1n l\u00e3i t\u1eeb 2 cho t\u1edbi 4 s\u1ed1 tr\u00ean t\u1ed5ng 5 s\u1ed1 gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0111\u00e3 k\u1ec3 tr\u00ean.<\/p>\n
N\u1ebfu ra c\u1ea3 5 con s\u1ed1 th\u00ec ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c 10 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7, s\u1ebd l\u00e0 12.5 * 480 = 6000k. Gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p s\u1ed1 \u0111\u00e1 3 v\u00e0 4, n\u1ebfu c\u00f3 s\u1ed1 v\u1ec1 nhi\u1ec1u th\u00eam 1 nh\u00e1y th\u00ec t\u00ednh l\u00e0 \u0103n n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/p>\n
K\u1ebft lu\u1eadn<\/span><\/h2>\nNh\u00ecn chung, c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 n\u00e0y r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. Kh\u00e1 gi\u1ed1ng v\u1edbi \u0111\u00e1nh nhi\u1ec1u c\u00e1i l\u00f4 xi\u00ean 2, 3, 4 m\u1ed9t l\u00fac nh\u01b0ng ti\u1ec1n x\u00e1c v\u00e0 t\u1ef7 l\u1ec7 \u0103n th\u00ec c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
Anh em ch\u01a1i s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u00f3 th\u1ec3 ch\u01a1i \u1edf mi\u1ec1n Nam. \u1ede mi\u1ec1n B\u1eafc kh\u00f4ng th\u1ea5y ph\u1ed5 bi\u1ebfn c\u00e1ch ch\u01a1i n\u00e0y. Ch\u01a1i \u0111\u00e0i mi\u1ec1n Nam r\u1ea5t kh\u00f3 v\u00ec c\u00f3 qu\u00e1 nhi\u1ec1u \u0111\u00e0i v\u00e0 kh\u00f3 soi c\u1ea7u b\u1eaft s\u1ed1. Tuy nhi\u00ean v\u1edbi c\u00e1ch \u0111\u00e1nh n\u00e0y, hy v\u1ecdng ch\u00fang t\u00f4i \u0111\u00e3 cho anh em th\u1ea5y \u0111\u01b0\u1ee3c m\u1ed9t l\u1ed1i ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1edbi cho m\u00ecnh. B\u1ea3n th\u00e2n V\u0169 th\u1ea5y c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 th\u1eadt s\u1ef1 h\u1eefu d\u1ee5ng. Do \u0111\u00f3 c\u0169ng mong anh em c\u00e2n nh\u1eafc ch\u01a1i c\u00e1ch n\u00e0y nhi\u1ec1u h\u01a1n.<\/p>\n<\/div>\n<\/div>\n<\/article>\n
<\/main><\/div>\n
T\u1ef7 l\u1ec7 \u0103n s\u1ed1 \u0111\u00e1 l\u00e0 1 : 12,5. M\u1ed9t tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t n\u1ebfu ch\u01a1i \u0111\u00e1 l\u00f4 2 c\u1eb7p th\u00ec ti\u1ec1n \u0103n s\u1ebd g\u1ea5p 25 l\u1ea7n ti\u1ec1n x\u00e1c (1:25)<\/p>\n
S\u1ed1 \u0111\u00e1 v\u1ed1n r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i x\u1ed5 s\u1ed1 l\u00f4 \u0111\u1ec1 mi\u1ec1n Nam. V\u00e0 trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 th\u00ec ti\u1ec1n l\u1eddi l\u00e3i khi \u0111\u00e1nh s\u1ed1 \u0111\u00e1 2, 3, 4, 5 s\u1ebd c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
\u0110\u00e1 l\u00f4 2 c\u00f3 ti\u1ec1n l\u00e3i c\u1ee5 th\u1ec3 nh\u01b0 th\u1ebf n\u00e0o?<\/span><\/h3>\n\u0110\u00e1 l\u00f4 2 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ch\u01a1i 1 c\u1eb7p l\u00f4 (1 v\u00f2ng d\u1ef1 th\u01b0\u1edfng theo c\u00e1ch n\u00f3i c\u1ee7a nhi\u1ec1u ch\u1ed7 kh\u00e1c).<\/p>\n
VD: \u0110\u00e1 l\u00f4 2 s\u1ed1 12-23 (1 v\u00f2ng)<\/p>\n
Khi ch\u01a1i \u0111\u00e1 l\u00f4 2, KQXS v\u1ec1 c\u1ea3 2 con l\u00f4 (kh\u00f4ng v\u1ec1 nhi\u1ec1u nh\u00e1y) th\u00ec anh em c\u00f3 ti\u1ec1n tr\u00fang 48*12.5=600k.<\/p>\n
Ti\u1ec1n l\u00e3i s\u1ed1 \u0111\u00e1 3 trong v\u00e0i tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3<\/span><\/h3>\n\u0110\u00e1 l\u00f4 3 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ra 3 con s\u1ed1, 3 con s\u1ed1 n\u00e0y s\u1ebd t\u1ea1o th\u00e0nh 3 c\u1eb7p s\u1ed1 (3 v\u00f2ng d\u1ef1 th\u01b0\u1edfng).<\/p>\n
VD: S\u1ed1 \u0111\u00e1 3 con l\u00f4 12 23 34 t\u1ea1o th\u00e0nh 3 c\u1eb7p 12-23; 23-34; 34-12 (3 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 3 con, n\u1ebfu v\u1ec1 2 con s\u1ed1 (v\u1ec1 1 c\u1eb7p l\u00f4) th\u00ec m\u1edbi xem l\u00e0 tr\u00fang s\u1ed1 \u0111\u00e1. C\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00fang \u0111\u01b0\u1ee3c chia c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 2 tr\u00ean t\u1ed5ng 3 s\u1ed1 (tr\u00fang 1 c\u1eb7p): ti\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang 2 s\u1ed1 v\u00e0 c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y. VD: \u0111\u00e1nh 11 22 33 v\u00e0 v\u1ec1 11; 22 v\u1ec1 2 nh\u00e1y, 33 c\u00e2m.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam n\u1eeda v\u00f2ng, t\u1ee9c l\u00e0 ti\u1ec1n x\u00e1c 1 c\u1eb7p l\u00f4 nh\u00e2n t\u1ef7 l\u1ec7 \u0103n c\u01b0a \u0111\u00f4i.
\n48 * 12.5 \/ 2 = 300k<\/li>\n - Tr\u00fang 2 s\u1ed1, trong \u0111\u00f3 c\u00f3 1 s\u1ed1 v\u1ec1 3 nh\u00e1y. VD: v\u1ec1 11 v\u00e0 22 v\u1ec1 3 nh\u00e1y, 33 kh\u00f4ng v\u1ec1.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam 1 v\u00f2ng.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang c\u1ea3 3 s\u1ed1 (t\u1ee9c v\u1ec1 c\u1ea3 3 c\u1eb7p) th\u00ec t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7 nh\u01b0 th\u01b0\u1eddng.
\n144 * 12.5 = 1800k<\/li>\n<\/ul>\n<\/div>\nC\u00e1ch ch\u01a1i S\u1ed1 \u0111\u00e1 4 c\u00f3 ti\u1ec1n l\u1eddi th\u1ebf n\u00e0o?<\/span><\/h3>\nT\u01b0\u1eddng t\u1ef1 ch\u00fang ta c\u00f3 ti\u1ebfp \u0111\u00e1 l\u00f4 4 l\u00e0 ch\u1ecdn ra 4 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 6 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (6 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 4 con, ch\u00fang s\u1ebd t\u1ea1o th\u00e0nh 6 c\u1eb7p, ch\u1ec9 c\u1ea7n c\u00f3 1 c\u1eb7p (t\u1ee9c l\u00e0 2 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1) v\u1ec1 th\u00ec anh em tr\u00fang s\u1ed1. Chia ra c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n- Tr\u00fang 1 c\u1eb7p: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.<\/li>\n
- V\u1ec1 3 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 3<\/li>\n
- V\u1ec1 c\u1ea3 4 s\u1ed1: t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7: 288 * 12.5 = 3600k<\/li>\n
- Trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00ean, n\u1ebfu c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y th\u00ec t\u00ednh ti\u1ec1n l\u00e3i th\u00eam n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 \u0111i\u1ec3m nh\u00e2n v\u1edbi t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/li>\n<\/ul>\n
Ti\u1ec1n l\u1eddi s\u1ed1 \u0111\u00e1 5 trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p<\/span><\/h3>\nS\u1ed1 \u0111\u00e1 5: ch\u1ecdn ra 5 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 10 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (10 v\u00f2ng)<\/p>\n
\u0110\u00e1nh s\u1ed1 \u0111\u00e1 5 c\u00f3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0103n ti\u1ec1n l\u00e3i t\u1eeb 2 cho t\u1edbi 4 s\u1ed1 tr\u00ean t\u1ed5ng 5 s\u1ed1 gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0111\u00e3 k\u1ec3 tr\u00ean.<\/p>\n
N\u1ebfu ra c\u1ea3 5 con s\u1ed1 th\u00ec ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c 10 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7, s\u1ebd l\u00e0 12.5 * 480 = 6000k. Gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p s\u1ed1 \u0111\u00e1 3 v\u00e0 4, n\u1ebfu c\u00f3 s\u1ed1 v\u1ec1 nhi\u1ec1u th\u00eam 1 nh\u00e1y th\u00ec t\u00ednh l\u00e0 \u0103n n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/p>\n
K\u1ebft lu\u1eadn<\/span><\/h2>\nNh\u00ecn chung, c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 n\u00e0y r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. Kh\u00e1 gi\u1ed1ng v\u1edbi \u0111\u00e1nh nhi\u1ec1u c\u00e1i l\u00f4 xi\u00ean 2, 3, 4 m\u1ed9t l\u00fac nh\u01b0ng ti\u1ec1n x\u00e1c v\u00e0 t\u1ef7 l\u1ec7 \u0103n th\u00ec c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
Anh em ch\u01a1i s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u00f3 th\u1ec3 ch\u01a1i \u1edf mi\u1ec1n Nam. \u1ede mi\u1ec1n B\u1eafc kh\u00f4ng th\u1ea5y ph\u1ed5 bi\u1ebfn c\u00e1ch ch\u01a1i n\u00e0y. Ch\u01a1i \u0111\u00e0i mi\u1ec1n Nam r\u1ea5t kh\u00f3 v\u00ec c\u00f3 qu\u00e1 nhi\u1ec1u \u0111\u00e0i v\u00e0 kh\u00f3 soi c\u1ea7u b\u1eaft s\u1ed1. Tuy nhi\u00ean v\u1edbi c\u00e1ch \u0111\u00e1nh n\u00e0y, hy v\u1ecdng ch\u00fang t\u00f4i \u0111\u00e3 cho anh em th\u1ea5y \u0111\u01b0\u1ee3c m\u1ed9t l\u1ed1i ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1edbi cho m\u00ecnh. B\u1ea3n th\u00e2n V\u0169 th\u1ea5y c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 th\u1eadt s\u1ef1 h\u1eefu d\u1ee5ng. Do \u0111\u00f3 c\u0169ng mong anh em c\u00e2n nh\u1eafc ch\u01a1i c\u00e1ch n\u00e0y nhi\u1ec1u h\u01a1n.<\/p>\n<\/div>\n<\/div>\n<\/article>\n
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\u0110\u00e1 l\u00f4 3 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ra 3 con s\u1ed1, 3 con s\u1ed1 n\u00e0y s\u1ebd t\u1ea1o th\u00e0nh 3 c\u1eb7p s\u1ed1 (3 v\u00f2ng d\u1ef1 th\u01b0\u1edfng).<\/p>\n
VD: S\u1ed1 \u0111\u00e1 3 con l\u00f4 12 23 34 t\u1ea1o th\u00e0nh 3 c\u1eb7p 12-23; 23-34; 34-12 (3 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 3 con, n\u1ebfu v\u1ec1 2 con s\u1ed1 (v\u1ec1 1 c\u1eb7p l\u00f4) th\u00ec m\u1edbi xem l\u00e0 tr\u00fang s\u1ed1 \u0111\u00e1. C\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00fang \u0111\u01b0\u1ee3c chia c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
- \n
- Tr\u00fang 2 tr\u00ean t\u1ed5ng 3 s\u1ed1 (tr\u00fang 1 c\u1eb7p): ti\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang 2 s\u1ed1 v\u00e0 c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y. VD: \u0111\u00e1nh 11 22 33 v\u00e0 v\u1ec1 11; 22 v\u1ec1 2 nh\u00e1y, 33 c\u00e2m.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam n\u1eeda v\u00f2ng, t\u1ee9c l\u00e0 ti\u1ec1n x\u00e1c 1 c\u1eb7p l\u00f4 nh\u00e2n t\u1ef7 l\u1ec7 \u0103n c\u01b0a \u0111\u00f4i.
\n48 * 12.5 \/ 2 = 300k<\/li>\n - Tr\u00fang 2 s\u1ed1, trong \u0111\u00f3 c\u00f3 1 s\u1ed1 v\u1ec1 3 nh\u00e1y. VD: v\u1ec1 11 v\u00e0 22 v\u1ec1 3 nh\u00e1y, 33 kh\u00f4ng v\u1ec1.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam 1 v\u00f2ng.
\n48 * 12.5 = 600k<\/li>\n - Tr\u00fang c\u1ea3 3 s\u1ed1 (t\u1ee9c v\u1ec1 c\u1ea3 3 c\u1eb7p) th\u00ec t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7 nh\u01b0 th\u01b0\u1eddng.
\n144 * 12.5 = 1800k<\/li>\n<\/ul>\n<\/div>\nC\u00e1ch ch\u01a1i S\u1ed1 \u0111\u00e1 4 c\u00f3 ti\u1ec1n l\u1eddi th\u1ebf n\u00e0o?<\/span><\/h3>\n
T\u01b0\u1eddng t\u1ef1 ch\u00fang ta c\u00f3 ti\u1ebfp \u0111\u00e1 l\u00f4 4 l\u00e0 ch\u1ecdn ra 4 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 6 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (6 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 4 con, ch\u00fang s\u1ebd t\u1ea1o th\u00e0nh 6 c\u1eb7p, ch\u1ec9 c\u1ea7n c\u00f3 1 c\u1eb7p (t\u1ee9c l\u00e0 2 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1) v\u1ec1 th\u00ec anh em tr\u00fang s\u1ed1. Chia ra c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
- \n
- Tr\u00fang 1 c\u1eb7p: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.<\/li>\n
- V\u1ec1 3 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 3<\/li>\n
- V\u1ec1 c\u1ea3 4 s\u1ed1: t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7: 288 * 12.5 = 3600k<\/li>\n
- Trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00ean, n\u1ebfu c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y th\u00ec t\u00ednh ti\u1ec1n l\u00e3i th\u00eam n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 \u0111i\u1ec3m nh\u00e2n v\u1edbi t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/li>\n<\/ul>\n
Ti\u1ec1n l\u1eddi s\u1ed1 \u0111\u00e1 5 trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p<\/span><\/h3>\n
S\u1ed1 \u0111\u00e1 5: ch\u1ecdn ra 5 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 10 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (10 v\u00f2ng)<\/p>\n
\u0110\u00e1nh s\u1ed1 \u0111\u00e1 5 c\u00f3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0103n ti\u1ec1n l\u00e3i t\u1eeb 2 cho t\u1edbi 4 s\u1ed1 tr\u00ean t\u1ed5ng 5 s\u1ed1 gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0111\u00e3 k\u1ec3 tr\u00ean.<\/p>\n
N\u1ebfu ra c\u1ea3 5 con s\u1ed1 th\u00ec ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c 10 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7, s\u1ebd l\u00e0 12.5 * 480 = 6000k. Gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p s\u1ed1 \u0111\u00e1 3 v\u00e0 4, n\u1ebfu c\u00f3 s\u1ed1 v\u1ec1 nhi\u1ec1u th\u00eam 1 nh\u00e1y th\u00ec t\u00ednh l\u00e0 \u0103n n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/p>\n
K\u1ebft lu\u1eadn<\/span><\/h2>\n
Nh\u00ecn chung, c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 n\u00e0y r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. Kh\u00e1 gi\u1ed1ng v\u1edbi \u0111\u00e1nh nhi\u1ec1u c\u00e1i l\u00f4 xi\u00ean 2, 3, 4 m\u1ed9t l\u00fac nh\u01b0ng ti\u1ec1n x\u00e1c v\u00e0 t\u1ef7 l\u1ec7 \u0103n th\u00ec c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
Anh em ch\u01a1i s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u00f3 th\u1ec3 ch\u01a1i \u1edf mi\u1ec1n Nam. \u1ede mi\u1ec1n B\u1eafc kh\u00f4ng th\u1ea5y ph\u1ed5 bi\u1ebfn c\u00e1ch ch\u01a1i n\u00e0y. Ch\u01a1i \u0111\u00e0i mi\u1ec1n Nam r\u1ea5t kh\u00f3 v\u00ec c\u00f3 qu\u00e1 nhi\u1ec1u \u0111\u00e0i v\u00e0 kh\u00f3 soi c\u1ea7u b\u1eaft s\u1ed1. Tuy nhi\u00ean v\u1edbi c\u00e1ch \u0111\u00e1nh n\u00e0y, hy v\u1ecdng ch\u00fang t\u00f4i \u0111\u00e3 cho anh em th\u1ea5y \u0111\u01b0\u1ee3c m\u1ed9t l\u1ed1i ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1edbi cho m\u00ecnh. B\u1ea3n th\u00e2n V\u0169 th\u1ea5y c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 th\u1eadt s\u1ef1 h\u1eefu d\u1ee5ng. Do \u0111\u00f3 c\u0169ng mong anh em c\u00e2n nh\u1eafc ch\u01a1i c\u00e1ch n\u00e0y nhi\u1ec1u h\u01a1n.<\/p>\n<\/div>\n<\/div>\n<\/article>\n
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